5c^2+10c^2-240c=0

Solution for 5c^2+10c^2-240c=0 equation:

5c^2+10c^2-240c=0

We add all the numbers together, and all the variables

15c^2-240c=0

a = 15; b = -240; c = 0;
Δ = b2-4ac
Δ = -2402-4·15·0
Δ = 57600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{57600}=240$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-240)-240}{2*15}=\frac{0}{30}
=0
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-240)+240}{2*15}=\frac{480}{30}
=16
$